矩阵的行列式计算¶
⭐常用性质¶
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\(|kA| = k^{n}|A|\)
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\(|A^{-1}| = \frac{1}{|A|}\)
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\((kA)^{-1} = \frac{1}{k}A^{-1}\)
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\(A^{*} = |A|A^{-1}\)
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\(|A^{*}| = |A|^{n - 1}\)
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\(|AB| = |BA| = |A||B|\)
例题¶
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设 \(A\) 为三阶矩阵,且 \(|A| = 2\),求 \(|3A|\),\(|A^{-1}|\),\(|A^{*}|\)
解:
\[ |3A| = 3^{3}|A| = 27 \times 2 = 54 \]\[ |A^{-1}| = \frac{1}{|A|} = \frac{1}{2} \]\[ |A^{*}| = |A|^{n - 1} = 2^{3 - 1} = 4 \] -
设 \(A\),\(B\) 都是 \(n\) 阶方阵,且 \(|A| = 3\), \(|B| = 2\), 求 \(|\frac{1}{3} A^{*}B^{-1}|\)
解:
\[ \begin{align} |\frac{1}{3} A^{*}B^{-1}| &= |\frac{1}{3} A^{*}||B^{-1}| \\ &= (\frac{1}{3})^{n} |A^{*}| |B^{-1}| \\ &= (\frac{1}{3})^{n} |A|^{n - 1} \frac{1}{|B|} \\ &= (\frac{1}{3})^{n} 3^{n - 1} \frac{1}{2} \\ &= \frac{1}{6} \end{align} \] -
设 \(A\) 为 \(n\) 阶方阵,且 \(|A| = 2\), 求 \(|(-\frac{1}{4}A)^{-1} + A^{*}|\)
解:
\[ \begin{align} |(-\frac{1}{4}A)^{-1} + A^{*}| &= |-4A^{-1} + |A|A^{-1}| \\ &= |-4A^{-1} + 2A^{-1}| = |-2A^{-1}| \\ &= (-2)^{n} \cdot \frac{1}{|A|} = (-2)^{n} \cdot \frac{1}{2} \\ &= (-1)^{n} \cdot 2^{n - 1} \end{align} \]